A reaction mixture contains 14.3 g of PCl_3 and 9.10 g of PbF_2. What mass of PbCl_2 can be obtained from the following reaction: 3PbF_2 + 2PCl_3 yields 2 PF_3 + 3PbCl_2. What mass of PF_3 is formed? What is the mass of the excess reactant? Please, Please, Please show steps. Thank you.
2007-05-01 15:14:05 · 1 answers · asked by me of course 2 in Science & Mathematics ➔ Chemistry
ALL these type questions require you to think in the sequence mass to moles to equation to other moles to other mass.
So, you find the mol weight of PCl3 and PbF2. Divide the grams by the mol weights to get moles.
The reaction tells you that for each 3 moles or PbF2 or 2 moles of PCl3, 2 moles of PF3 are formed. Ideally, you actually have these reactants in a 3 mole to 2 mole ratio, but probably you dont. From what you have in moles for each of the reactants, you figure which gives you the LEAST PF3 product, and figure the moles of that.
Now you find the mole weight of PF3 and multiply that by the moles that you determined.
2007-05-01 15:25:52 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋