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Ok its not actually a paradox but here goes,

Lets say we have a distance function s(t)=-|t+3|

The derivative at 3 is undefined at 3 because it is an absolute value

The interval is from 0 to 6. By the mean value theorem some point c has to have a derivative of 0.

Therefore the velocity at 3 is 0, which seems logical, but that means the derivative at 3 is 0 which it isnt!

What do you think?

2007-05-01 15:02:17 · 2 answers · asked by The Phat Whale 3 in Science & Mathematics Mathematics

V(t) is not -1 because it is an absolute value!

2007-05-01 15:11:11 · update #1

2 answers

First, the derivitive of this would be v(t)= -1
Since this doesn't have a minimum or maximum point, the rest of your arguement is pointless.

2007-05-01 15:09:55 · answer #1 · answered by cattbarf 7 · 1 1

I'm truly sorry, but I don't understand a word you wrote.

2007-05-01 22:10:27 · answer #2 · answered by lucky_greek 2 · 0 2

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