Pythagorean theorem math problem?

Question

did i do this right
a=8,b=15 i got c=17 is that right

Answer 1

Yes it is. Good job!

This is another of the basic Pythagorean Triples. (These are triples you see, just multiplied. For instance, you might see a right triangle with sides of 16 and 30 (twice the 8 and 15) so you know from memory that the "c" side must be twice the 17, or 34. The same with 3,4,5 and 5,12,13.)

Answer 2

If you want to ask if a triangle with those sides is right-angled, your answer is Yes. The triangle is right-angled at the vertex opposite the longest side c = 17.

Here's why. The Pythagorean theorem states that if a triangle is right-angled, then the sum of the squares of the legs = the square of the hypotenuse. The hypotenuse is the longest side and is the side opposite the vertex with the right angle.

The converse of the theorem is also true. If any triangle has three sides such that the sum of the square of two sides is equal to the square of the largest side, then the triangle is right angled at the vertex opposite the largest side.

You can find the proof of this here:
http://en.wikipedia.org/wiki/Pythagorean_theorem#Converse

Now, using the converse, we obtain the answer to your question.
a^2 = 64
b^2 = 225
a^2 + b^2 = 225 + 64
= 289 = c^2

Since the sides of the triangle satisfy the pythagoras theorem, it is right-angled at the vertex opposite side c

Answer 3

Yes

Answer 4

Pythagorean theorem states that a^2 + b^2 = c^2.

8^2=64
15^2=225
64+225=289
sqrt(289)=17


yes, your answer is correct

Answer 5

Yes.

Answer 6

Yes.

Answer 7

Yes.

Answer 8

considering the two the legs are equivalent, cause them to the two X you positioned it up as X squared plus X squared = 40 six squared Which then will become 2X squared = 40 six divide by using two and get X squared = 23 sq. root the two factors and get the legs as each being radical 23

Answer 9

Yes, assuming c is the longest side.

Answer 10

That is what I have.