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Please walk me through how you do it.

2007-05-01 14:11:32 · 6 answers · asked by Jenni T 1 in Science & Mathematics Mathematics

6 answers

since they both have (x + y)
the answer would be (3 + a) (x + y) because the (x + y) is a pair so it can be taken out right? so what is left is the other factor, (3 + a).

2007-05-01 14:14:40 · answer #1 · answered by t_nguyen62791 3 · 0 0

Its easy.......as you see the (x+y) is the same in both of them so....

you take the 3 from the first and then the +a from the second and combine them to form.......(3+a)....since the (x+y) is the same, thats the other half of the equation so it becomes (3+a)(x+y) when you have a problem like this, where there is something like (x+y) in both, you use that

2007-05-01 21:26:19 · answer #2 · answered by RubiaBonita 2 · 0 0

The common factor is (x+y). Factor that out and you have (3+a)(x+y)

2007-05-01 21:14:00 · answer #3 · answered by dodgetruckguy75 7 · 0 0

ok well first you cant simplfy x +y any more so you work on the outside so 3 times a = 3A then x plus x equals 2x and same with y so the answer is 3a+2x+2y hope this helps

2007-05-01 21:15:03 · answer #4 · answered by carlosgarcia1221 1 · 0 0

Let z be (x+y).

3(x+y) + a(x+y)
=> 3z + az
=> z(3 + a)
=> (x + y)(3 +a)

This method is called grouping.

2007-05-01 21:16:07 · answer #5 · answered by QiQi 3 · 0 0

3*x=3x
3*y=3y
a*x=ax
a*y=ay

3x+3y+ax+ay

2007-05-01 21:15:23 · answer #6 · answered by Dave aka Spider Monkey 7 · 0 0

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