How would u calculate the pH and pOH of a final solution??

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How would u calculate the pH and pOH of a final solution??

How would u calculate the pH and pOH of the final solution if u have 4.6L of .025M H2SO4 and 1.7L of .125M NaOH and a 74% yield??? I know you have to do something with the excess reactant but i dont know what. PLZ help!!!

2007-05-01 13:29:51 · 1 answers · asked by lucky 1 in Science & Mathematics ➔ Chemistry

1 answers

moles of H2SO4 = .115

Moles of NaOH = 0.2125

H2SO4 is the excess reactant.

Acid left = 0.0299

So, pH = -log(0.0299)

2007-05-01 22:43:18 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋