Solve each quadratic equation by factoring thanks!
2007-05-01 13:12:34 · 6 answers · asked by Rei 1 in Science & Mathematics ➔ Mathematics
1. x(x+7)
2. 9(x-3)(x+1)
2007-05-01 13:16:05 · answer #1 · answered by Gman 2 · 0⤊ 1⤋
x(x + 7) = 0
x = 0 x+ 7 = 0
x = 0 x = -7
9x^2 - 18x - 27 = 0
9(x^2 - 2x - 3) = 0
9(x - 3)(x + 1) = 0
(x - 3)(x + 1) = 0
x = 3 x = -1
2007-05-01 20:17:32 · answer #2 · answered by shifty 2 · 0⤊ 0⤋
x^2 + 7x = 0
x * (x + 7) = 0
x = 0 or x = -7
9x^2 - 18x + 27
9(x^2 - 2x + 3)
9 * (x - 3) * (x + 1)
x = 3 or x = -1
2007-05-01 20:16:50 · answer #3 · answered by TychaBrahe 7 · 0⤊ 0⤋
x^2+7x=0
x(x+7)=0
x = 0, -7
9x^2=18x+27
x^2 - 2x -3 =0 (divide all by 9)
(x-3)(x+1)=0
x = 3, -1
2007-05-01 20:16:35 · answer #4 · answered by looikk 4 · 0⤊ 0⤋
1. x^2+7x=0
x(x+7)=0
x=-7
2. 9x^2=18x+27
9x^2-18x-27=0
9(x^2-2-3)
9(x-3)(x+1)
x=3, x=-1
2007-05-01 21:46:33 · answer #5 · answered by bootis32 6 · 0⤊ 0⤋
x^2-7x=0
x(x-7)=0
x=0 or x=7
9x^2-18x-27=0
9(x^2-2x-3)=0
(x+1)(x-3)=0
x=-1 or x=3
2007-05-01 20:19:26 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋