a coin is tossed and a number cube is rolled. Find the probability of p(tails and 3)?

Answer 1

To find the probability of a series of independent event, such as the two event in this problem, first, you find the probability of each individual event. Then you multiply the two probabilites together:

Basically, P(A and B) = P(A) * P(B):

P(tails) = 1 favored outcomes/2 possible outcomes = 1/2

P(3) = 1 favored outcome/6 possible outcomes = 1/6

P(tails and 3) = 1/2 * 1/6 = 1/12

Answer 2

The chance of heading tails is 1/2 and the chance of getting a 3 is 1/6. To get the probability of both you have to multiply both of those chances. So 1/2*1/6= 1/12. So P=1/12

Answer 3

Probability of tails = 1/2
Probability of 3 = 1/6
Probability of both occuring = 1/2 * 1/6 = 1/12

Answer 4

P(x and y) = P(x) * P(y)

(1/2) * (1/6) = 1/12
.

Answer 5

These are two independent events and as we have learned to caluclate the probabilit yof 2 independent events, multiply the two probaiblities together to get the prob of both occuring.

P(head) = 1/2
P(3) = 1/6
p(head and 3) = 1/2 * 1/6 = 1/12

Answer 6

(1/2) x (1/6) = 1/12