2007-05-01 12:47:19 · 9 answers · asked by Gerrad G 1 in Science & Mathematics ➔ Mathematics
4 √3
2007-05-01 12:50:46 · answer #1 · answered by Gman 2 · 0⤊ 0⤋
2√3 + 3 √3 - √3
(2 + 3 - 1) * √3
4 √3
2007-05-01 12:49:58 · answer #2 · answered by TychaBrahe 7 · 0⤊ 0⤋
Showing every needed step, this is √(4*3) + √(9*3) - √3
= (2 + 3 - 1)* √3
= 4 √3.
Live long and prosper.
2007-05-01 12:50:13 · answer #3 · answered by Dr Spock 6 · 0⤊ 0⤋
So here, what you want to notice is that all three terms under the radical have factors of three. 12=3*4, 27=3*9, and 3=3*1. With roots, rt(12) is equal to the product of its factors. So, rt(12)=rt(3)*rt(4), and rt (4)=2. rt(27)=rt(3)*rt(9), and rt(9)=3. rt(3)=rt(3)*rt(1), and rt(1)=1. So, you're left with 2rt(3)+3rt(3)-rt(3)=5rt(3)-rt(3). So the answer is 4rt(3), or 4 multiplied by the square root of 3.
2007-05-01 12:55:36 · answer #4 · answered by LittleLauraAnne 1 · 0⤊ 0⤋
~=square root sign
~12+~27-~3
~39-~3
~36
~6
2007-05-01 12:54:14 · answer #5 · answered by brody t 2 · 0⤊ 0⤋
2 rad 3 + 3 rad 3 - rad3
4 rad 3
2007-05-01 12:50:00 · answer #6 · answered by shifty 2 · 0⤊ 0⤋
2 sq rt 3 + 3 sq rt 3 - sq rt 3 =
4 sq rt 3
2007-05-01 12:49:47 · answer #7 · answered by richardwptljc 6 · 0⤊ 0⤋
4Rad 3
2007-05-01 12:52:26 · answer #8 · answered by Katie A 1 · 0⤊ 0⤋
sqrt 12+sqrt27-sqrt3=
2sqrt3+3sqrt3-sqrt3=4sqrt 3
2007-05-01 13:07:06 · answer #9 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋