You have 188 feet of fencing to enclose a rectangular region. What is the maximum area?
How do I solve this?
Thanks for any help,
Jennifer
2007-05-01 12:45:05 · 3 answers · asked by jennifermlayne 2 in Science & Mathematics ➔ Mathematics
The maximum area inside a rectangle is when the rectangle is a square. So you need to find a square with perimeter 188.
The side then is 188/4 = 47.
The area is side^2 = 47^2 = 2209 sq ft.
Proove it?
Imagine a rectange with side x. Then the other side must be 96-x, because 2x + 2(96-x) = 188.
A(x) = x * (96 - x)
A(x) = 96x - x^2.
A(x)/dx = 96 - 2x = 0
-2x = -96
2x = 96
x = 47
2007-05-01 12:54:31 · answer #1 · answered by TychaBrahe 7 · 0⤊ 0⤋
2209 sq feet.
a square has the max area
188 divided by 4 is 47
each side being 47, area is 2209
2007-05-01 19:53:27 · answer #2 · answered by shifty 2 · 0⤊ 0⤋
2209 ft^2
2007-05-01 20:00:46 · answer #3 · answered by Gman 2 · 0⤊ 0⤋