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How do u solve this problem?

A local theme park had 840 visitors last weekend and collected a total of $11,640 from admission tickets. If an adult's admission ticket is $18 and a child's ticket is $12, how many adults and how many childern visited the park?

2007-05-01 12:42:36 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

A + C = 840 or
18A + 18C = 15120

18A + 12C = 11640

subtract

6C = 3480
C = 580
A = 260

2007-05-01 12:49:01 · answer #1 · answered by TychaBrahe 7 · 0 1

you can set up two equations for it and then solve

if you let x = number of adults and y = number of children, you get

18x + 12y = 11,640

Then, you can also get that x + y = 840
because you know that the number of children and adults together makes up the total amount of visitors.

You would then find x by subtracting y from each side of the second equation... x = 840 - y

You can put this into your first equation like so:

18(840 - y) + 12y = 11,640
which simplifies to:

15120 - 18y + 12y
then you subtract from both sides to get

-6y = -3480
then you divide by -6 to be left with just y and you get:

y = 580!!

that means there were 580 children that visited....if you put that into the original second equation, you get

x + 580 = 840
x = 260!!

(260 adults)

Voila! Hope this helped.

2007-05-01 19:50:20 · answer #2 · answered by Claire 3 · 0 0

Simultaneous equations...

x = number of adult tickets sold
y = number of child tickets sold

x + y = 840
18x + 12y = 11640

I make that x=260, y=580

2007-05-01 19:53:54 · answer #3 · answered by joncummins1968 4 · 0 0

this is solved in the same way as
the question you asked yesterday.
plug in the numbers and solve.

2007-05-01 19:49:16 · answer #4 · answered by jaybee 4 · 0 2

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