2007-05-01 12:24:42 · 8 answers · asked by Gerrad G 1 in Science & Mathematics ➔ Mathematics
11√7 - 4√7
Treat it like 11x - 4x.
Your answer is
7√7
But √7 = 7^(1/2), so we have
(7^1)(7^(1/2))
Add the exponents, to get
7^(3/2)
2007-05-01 12:27:28 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
You don't really have "like terms," but you have "like radicals."
In order to combine like radicals, you combine the coefficients like you would with like terms.
11â7 - 4â7 = 7â7
2007-05-01 19:29:01 · answer #2 · answered by wugit 1 · 0⤊ 0⤋
7 and the square root of 7
2007-05-01 19:27:38 · answer #3 · answered by quackie81 3 · 0⤊ 0⤋
â7 is the like term
11-4=7
Answer 7 â7
2007-05-01 19:28:19 · answer #4 · answered by Staley 3 · 0⤊ 0⤋
Factor out sqrt(7) and you have sqrt(7) (11-4) = 7sqrt(7)
2007-05-01 19:27:19 · answer #5 · answered by dodgetruckguy75 7 · 0⤊ 0⤋
7 square roots of seven (i don't know how to do the square root symbol, sorry)
2007-05-01 19:27:49 · answer #6 · answered by silly girl 2 · 0⤊ 0⤋
i hav a question
how do u do that sq. rt. symbol?
besides alternatively writing a frational exponent?
2007-05-01 19:30:10 · answer #7 · answered by deathbykindnes 3 · 0⤊ 0⤋
11sqrt7-4sqrt7=7sqrt7
2007-05-01 20:22:59 · answer #8 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋