Factor completely:
4x^2 + 44x + 96
2007-05-01 12:22:18 · 4 answers · asked by Simone J 1 in Science & Mathematics ➔ Mathematics
All the terms are divisible by 4, so factor out a 4.
4(x^2 + 11x + 24)
Now ask yourself "what factors of 24 add up to 11?" The factors are 8 and 3 because 8*3 = 24 and 8+3 = 11
Answer: 4(x+8)(x+3)
2007-05-01 12:27:22 · answer #1 · answered by MsMath 7 · 2⤊ 1⤋
First thing you should do is to factor out the largest common factor from the function (in this case "4")
4(x^2+11x+24) Then you factor the inside...
two numbers that add to 11 and multiply to 24
8 & 3
4(x+3)(x+8)=4x^2+44x+96)
2007-05-01 19:29:03 · answer #2 · answered by wahiv4 3 · 3⤊ 0⤋
First, take out the common factor, 4.
You get 4(x²+11x+24).
Now look for 2 whole numbers whose sum is 11
and whose product is 24. They are 8 and 3.
So your final result is 4(x+8)(x+3).
2007-05-01 19:37:53 · answer #3 · answered by steiner1745 7 · 3⤊ 0⤋
4(X+3)(X+8)
2007-05-01 19:29:00 · answer #4 · answered by hustolemyname 6 · 1⤊ 0⤋