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Factor each polynomial, if possible. If the polynomial cannot be factored, write prime.
1. (4p-9q)squared -1
2. 25xsquared - (2y-7z)squared

2007-05-01 12:05:19 · 5 answers · asked by lovely 1 in Science & Mathematics Mathematics

5 answers

Question 1
(4p - 9 q)² - 1
= [(4p - 9q) - 1].[(4p - 9q) + 1]
= [4p - 9q - 1].[4p - 9q + 1]

Question 2
(5x)² - (2x - 7z)²
[(5x) - (2x - 7z)].[5x + (2x - 7z)]
(3x + 7z).(7x - 7z)
7.(3x + 7z).(x - z)

2007-05-01 21:46:28 · answer #1 · answered by Como 7 · 0 0

These are both differences of two squares. The basic factoring of DTSs is x^2 - y^2 = (x+y)(x-y). So...

1. (4p-9q+1)(4p-9q-1)
2. [5x + (2y - 7z)][5x - (2y - 7z)]
which simplifies to (5x + 2y - 7z)(5x - 2y + 7z)

2007-05-01 19:13:05 · answer #2 · answered by wugit 1 · 0 0

1.
(4p-9q)^2 - 1
= (4p-9q+1)(4p-9q-1)

2.
(25x)^2 - (2y-7z)^2
= [25x+(2y-7z)][25x-(2y-7z)]
= [25x+2y-7z][25x-2y+7z]

Please note that a^2 - b^2 = (a+b)(a-b)

2007-05-02 21:39:11 · answer #3 · answered by Kemmy 6 · 0 0

Hi
This looks like a HW exercise so I am not going to do it for you.

It is based on the idea.......

whatsit squared - thingamy squared = (whatsit - thingamy)(whatsit + thingamy)

you just have to identify the terms, for example

(abc) squared - (def) squared = (abc - def)(abc + def)

Try your own questions on it

2007-05-02 01:17:58 · answer #4 · answered by fred 5 · 0 0

yea what grade r u in? i dont think i can help u because im in 8th grade pre-algebra so yea im in the dumb class

2007-05-01 19:13:56 · answer #5 · answered by Anonymous · 0 0

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