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5 answers

Do the Euclidean distance for points in 1-D. i.e.
distance = squareroot(p(x)-q(x))

Let P=p(x)=7,7
Let Q=q(x)=2.5

distance = sqrroot((7,7-2.5)sqared) or absolutevalue(7.7-2.5)

you can also reverse the 7.7 and 2.5, and the answer comes out the same:

=5.2

2007-05-01 10:12:49 · answer #1 · answered by InfiniteCutness 2 · 0 0

Are you referring to coordinate points at (7, 7) and (2, 5)?

2007-05-01 17:09:51 · answer #2 · answered by zeb 4 · 0 0

I beilive you are asking to use those coordinate points.

D=sqrt((7-2)^2+(7-5)^2)
D=sqrt(25+4)
D=sqrt(29)
D= aprox. 5.3851648

2007-05-01 17:16:34 · answer #3 · answered by Controlfreak38 6 · 0 0

√((7 - 2)^2 + (7 - 5)^2)

2007-05-01 17:13:02 · answer #4 · answered by Helmut 7 · 0 0

5.2, its just 7.7-2.5

2007-05-01 17:08:24 · answer #5 · answered by Anonymous · 0 0

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