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At what depth beneath the surface of a lake is the absolute pressure 3 times the atmospheric pressure of 1.01x10^5 Pa that acts on the lake's surface?

2007-05-01 09:44:30 · 3 answers · asked by Anonymous in Science & Mathematics Earth Sciences & Geology

3 answers

The pressure at a depth of h metres is given by:
p = p0 + density * g * depth

where :

p = pressure (Pa)
p0 = atmospheric pressure (1.01*10^5 Pa)
density (of water) = 998 kg/m^3
g = 9.81 m/s^2

At 3 times atmospheric pressure, p = 3.03*10^5 Pa.

3.03*10^5 = 1.01*10^5 + 998 * 9.81 * depth

Therefore, depth = (3.03*10^5 - 1.01*10^5) / (998 * 9.81)
= 20.6 metres

2007-05-01 11:06:25 · answer #1 · answered by falzoon 7 · 0 0

It has been a long time sense I went Scuba diving but I believe it will increase 1 atmosphere every 33 ft down.

2007-05-01 10:09:50 · answer #2 · answered by JOHNNIE B 7 · 0 0

Bosh isn't being himself. He is a low post player. But, you see him settling for jumpers. Now, they aren't falling for him and he wants to go back to the low post. If Bosh continues to play low post (which Heat need anyone), he will stay in Miami. Wade and LeBron definitely aren't leaving Miami lol.

2016-05-18 02:36:24 · answer #3 · answered by patrick 3 · 0 0

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