If the amplitude of a sound wave is increased by a factor of four, how does the energy carried by the sound wave in a given time and interval change?
2007-05-01 09:37:14 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The energy will be proportional to the area of the wave (in this case should be about 4 times as large).
2007-05-01 09:46:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
That is a small increase,for instance if u adjust the volume the smallest change that most people can detect is 3dB . now the 4 times is 6dB . the max sound or noise level is 85dB or more u should use hearing protection.
2007-05-01 09:45:09 · answer #2 · answered by JOHNNIE B 7 · 0⤊ 0⤋
v^2 = u^2 + 2as is the equation to apply for this. on the grounds which you're decelerating, acceleration is detrimental. on the grounds that v is to be 0, u^2 = 2as 65mph = 29.06 m/s (29.06)^2 = 4s s = 211.12 Sorry, Bambi, no longer common breaks! P.S. - that's the brakes on your vehicle.......
2016-12-28 06:45:58 · answer #3 · answered by palo 3 · 0⤊ 0⤋
i think energy prop. to (amp)^2
so it increases 16 times....i dunno.just a guess...
2007-05-01 09:47:02 · answer #4 · answered by nice_dude 1 · 0⤊ 0⤋