What is the eighth term of the geometric sequence whose first three terms are 3, 6 and 12?
192
48
768
384
2007-05-01 09:19:52 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3*2^7=384
2007-05-01 09:23:26 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
384
2007-05-01 09:29:14 · answer #2 · answered by Mowis 3 · 0⤊ 0⤋
384
2007-05-01 09:28:47 · answer #3 · answered by Fordman 7 · 0⤊ 0⤋
3 * 2^(n-1)
3 * 2^7 = 384
2007-05-01 09:24:02 · answer #4 · answered by Dave 6 · 0⤊ 0⤋
3, 6, 12, 24, 48, 96, 192, 384
multiply each of the values( 1, 2, 4, 8,16, 32, 64, 128) with three.
2007-05-01 09:26:25 · answer #5 · answered by meghanasharma 1 · 0⤊ 0⤋
common ratio r=2
first term a=3
term require n=8
so applying formula of nth term or G.P.
nth term=ar^(n-1)
=3*2^(8-1)
=3*2^7
=384
so answer is 384
2007-05-01 09:32:17 · answer #6 · answered by yash 1 · 0⤊ 0⤋
384.. each term is doubled
2007-05-01 09:24:03 · answer #7 · answered by Anonymous · 0⤊ 0⤋
each term doubles the previous term,so
3,6,12,24,48,96,192,384.
384 is the 8th term
2007-05-01 09:25:59 · answer #8 · answered by Anonymous · 0⤊ 0⤋
use this formula to figure it out.
8=D
you should get it quickly...
2007-05-01 09:24:37 · answer #9 · answered by nick h 2 · 0⤊ 0⤋