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Mg (OH)2 + HCL ------> H2O + MgCl2

2007-05-01 09:15:15 · 7 answers · asked by Candice 3 in Science & Mathematics Chemistry

7 answers

1. There are two "Cl"s on the right side, so put a "2" in front of HCl on the left side.

2. There are two oxygens on the left side (in the magnesium hydroxide), so put a "2" in front of "H2O" on the right side to balance out the oxygen.

3. The equation is now balanced.

2007-05-01 09:34:23 · answer #1 · answered by Skepticat 6 · 0 0

Mg(OH)2 + 2 HCl ---> 2 H2O + MgCl2

If you look at the reaction you can tell it's a double replacement reaction (both cations are switched around) It may be helpful to write H2O as HOH to see the H comes from HCl and the OH comes from Mg(OH)2. First realize you need to balance the Cl so write down 2 HCl. Then realize you need to balance the H2O because there are 2 OH in the MgOH. It's really alot of guess and test until you get used to it. But practice helps. And always check your answer by counting up the number of each element on each side until it gets easier for you.

2007-05-01 09:22:56 · answer #2 · answered by Anonymous · 0 0

First, you have to make sure that the elements balance on both sides. Here, there is 1 "Cl" on the left and two on the right, so we will have double the HCl. Doing this leads us to 4 "H" and 2 "O" on the left, but only 2 "H" and 1 "O" on the right. So we double the H2O as product. This completes our changes and the balanced eqtn is
Mg(OH)2 + 2HCl --> 2H2O + MgCl2

2007-05-01 09:21:25 · answer #3 · answered by cattbarf 7 · 0 0

Start with making sure everything on each side is equivalent, except for H and O (leave those for last). Hint: the number for Mg(OH)2 is 1.

2007-05-01 09:25:06 · answer #4 · answered by chemicalcajun 4 · 0 0

Mg (OH)2 + 2HCL --> 2H20 + MgCl2

2007-05-01 09:19:36 · answer #5 · answered by Duchess Ella 3 · 0 0

Just add a bit more H2O. Otherwise, use a better scale.

2007-05-01 09:19:34 · answer #6 · answered by CMK 3 · 0 1

Mg (OH)2 + 2HCL ------> 2H2O + MgCl2

2007-05-01 09:18:48 · answer #7 · answered by Hang 3 · 0 0

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