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A horse can exert a horizontal force of 3.5 x 104 N on a rope that passes over a pulley to lift loads vertically. What is the acceleration of a load of weight:

3.5 x 104 N? (Neglect the masses of the rope and pulley)
3.0 x 104 N? (Neglect the masses of the rope and pulley)

2007-05-01 07:25:20 · 1 answers · asked by keith c 1 in Science & Mathematics Physics

1 answers

using F=m*a
and looking at a free body diagram of the load
T=m*a-m*g
we know that T=3.5x10^4 N
if the load is the same as the tension then no acceleration occurs

for the second one
m*g=3.0x10^4
m=3.0x10^4/9.81

m*a=.5x10^4
a=.5*9.81/3 m/s^2

j

2007-05-02 05:44:22 · answer #1 · answered by odu83 7 · 0 0

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