There are an infinite number of points.
You could never list them all.
I'll show you how to find them.
You can solve for y by subtracting 3x from each side.
y = -3x + 3
When x = 0,
y = -3(0) + 3
y = 0 + 3
y = 3
So (0,3) is a point on the graph.
When x = 1,
y = -3(1) + 3
y = -3 + 3
y = 0
So (1,0) is a point on the graph.
2007-05-01 07:21:08
·
answer #1
·
answered by MsMath 7
·
2⤊
3⤋
change the graph into y = mx + c
i.e. y = -3x + 3
and then you know it crosses the y-axis at (0,3)
and it has a gradient of -3, and so another point on the line would be (1,0)
and then just draw a line through the points !
2007-05-01 14:23:02
·
answer #2
·
answered by Richard D 2
·
1⤊
0⤋
I agree that there are an infinate amount of points
maybe you are asking about the intercepts?
3(0) + y-int = 3 ....... y-int= 3
3x-int+ 0 = 3 , 3x-int = 3, x-int = 1
hope that was what you were looking for
intercepts: (0,3) and (1,0)
2007-05-01 14:23:25
·
answer #3
·
answered by bob 3
·
2⤊
0⤋
- 3x + 3 =y Slope intercept form slope -3/1 y-intercept 3
2007-05-01 14:24:10
·
answer #4
·
answered by dwinbaycity 5
·
0⤊
0⤋
oh boy! last time i took math was a zillion years ago stastics. i think it is y=3x-3 then it won't be so hard to find the y and x points is it? for the next time do your own work!!
2007-05-01 14:23:44
·
answer #5
·
answered by dorsey 2
·
0⤊
0⤋
x = 0
3x + y = 3
3(0) + y = 3
0 + y = 3
y = 3
ordered Pair
(0, 3)
- - - - - - - - -
y = 0
3x + y = 3
3x + 0 = 3
3x = 3
3x / 3 = 3 / 3
x = 3 / 3
x = 1
Ordered pair
(1, 0)
- - - - - - - - - - -s-
2007-05-01 14:55:05
·
answer #6
·
answered by SAMUEL D 7
·
2⤊
0⤋
Simple algebra. Figure out the equation
2007-05-01 14:23:13
·
answer #7
·
answered by Michael T 2
·
0⤊
2⤋
(0,3) and (1,0)
2007-05-01 14:22:14
·
answer #8
·
answered by Como 7
·
1⤊
0⤋