solve using the square root property x^2+48=0?

2007-05-01 07:03:08 · 2 answers · asked by Kathleen 1 in Science & Mathematics ➔ Mathematics

x² + 48 = 0

x² + 48 - 48 = 0 - 48

x² = - 48

√x² = i√48

√x² = √16 i√3

x = 4i√3

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2007-05-01 07:16:18 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋

x^2+48=0
x^2 = -48
x = sqrt(-48) = 4i*sqrt(3)

2007-05-01 14:08:02 · answer #2 · answered by Chad H 3 · 0⤊ 0⤋

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