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Huge number of Galaxy exploration spaceships was launched
from the Earth, all of them in the plane of the Galaxy.

Except from those ships, which travel ahead of others on the
frontier, each ship X has exactly 7 nearest spaceships, all seven
at the same distance from X as wieved by the captain of X.

What is relative speed v of all 7 closest spaceships
with respect to X?

2007-05-01 06:17:30 · 3 answers · asked by Alexander 6 in Science & Mathematics Physics

3 answers

Of course, I can always suppose that the fleet of starships form 2 levels of triangular tilings, so that, indeed, except for the extremities, every starship has exactly 7 nearest neighbors at equal distances. In this case, the relative velocity is unity, and the whole thing moves en masse.

The entire fleet has to be coplanar? Well, now we're talking about heptagon tilings, and there aren't too many ways of doing that, even in hyperbolic, relativistic space. But the link below does show an example of a heptagon tiling, so that every starship has exactly 7 "closest" neighbors. Maybe in some hyperbolic, relativistic space all the "closest" neighbors are at equal distances, but I'm too tired to figure out if this can be true.

2007-05-02 19:52:56 · answer #1 · answered by Scythian1950 7 · 0 0

Anyone with a best answer ratio as high as yours is suspect. Are you asking and answering your own questions??

The speed would be 0 with respect to x.

2007-05-01 06:22:20 · answer #2 · answered by Anonymous · 0 1

time

2007-05-01 06:23:58 · answer #3 · answered by digidy 1 · 0 0

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