Please show work
2007-05-01 06:12:06 · 11 answers · asked by tzc_1 1 in Science & Mathematics ➔ Mathematics
try to set alone in one side the X
so first you try to take away the 3 by dividing both side by it.
So you have
X^2=63/3
X^2=21
so X will we the +-sqr of 21
2007-05-01 06:19:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The answer is 3sqrt 3
First, you divided 3 on both side to get rid of 3 on the left side
x^2 = 63/3
= 21
Then, sqrt both side to get rid of the square on the left side
sqrt X^2 = sqrt 21
x = sqrt21 or 3sqrt of 3
2007-05-01 06:25:39 · answer #2 · answered by jj_angel99 1 · 0⤊ 0⤋
3 x² = 63
x² = 63/3
x² = 21
x = ± √21
x = ± 4.5826
2007-05-01 06:22:12 · answer #3 · answered by Pranil 7 · 0⤊ 0⤋
3X^2=63
X^2 = 63/3
X= SQRT(63/3)
Knowing that square root gives +/- so, answers are
x= +/- 4.58258
2007-05-01 06:18:38 · answer #4 · answered by Anonymous · 0⤊ 0⤋
divide both sides of the equation by 3
x^2 = 21
take the square root of both sides
x = + or - sqrt of 21
2007-05-01 06:18:56 · answer #5 · answered by Ray 5 · 0⤊ 0⤋
3X=ROOT OVER 63
X=7.937253933/3
X= 2.645751311
X=2.65(3 Significant figures)
2007-05-01 06:19:56 · answer #6 · answered by sophie 2 · 0⤊ 0⤋
3x^2 = 63
x^2 = 21
x= pos/neg sqrt21
2007-05-01 06:18:40 · answer #7 · answered by lizzie 3 · 1⤊ 0⤋
63/3=x^2
x^2=21
x=+/-sqrt(21)
2007-05-01 06:21:27 · answer #8 · answered by Superconductor 3 · 0⤊ 0⤋
isolate x^2: x^2 = 21
take a sq. root of both sides: x = +/- 4.58
2007-05-01 06:19:01 · answer #9 · answered by Ana 4 · 0⤊ 0⤋
x² = 21
x = ± √21
x = ± 4.58
2007-05-01 06:19:12 · answer #10 · answered by Como 7 · 0⤊ 0⤋