Factor Completly: X^2+3X-10?

Question

please show work for future reference

Answer 1

This is a simple case of factoring quadratics. (A "quadratic" is a polynomial that looks like "ax^2 + bx + c", where "a", "b", and "c" are just numbers.)

in your case X^2 + 3x - 10

You need to find factors of 10 that added results on 3.
-10 = -5*2
- 10= 5* -2
but
-5+2= -3
5-2=3
so the numbers are 5 and -2
(x+5)(x-2)

Answer 2

X^2+3X-10=(x-2)(x+5)

Answer 3

Find two numbers, a & b, such that a + b = 3 and ab = -10.
The factors of -10 to choose are: a = 5 & b = -2.
x² + 3x - 10 = (x + a)(x + b) = (x + 5)(x - 2).

Answer 4

since you have two x's one goes in each parentheses and because 10 is negative your going to have one + and one - so
(x+?) (x-?)
now the factors of 10 are 1 and 10 and 2 and 5 now 1 and 10 obviously don't subtract to make 3 so it must be 2 and 5 and because 3 is positive the bigger number goes after the + and the smaller number after the - so your answer is
(x+5)(x-2)

Answer 5

Since it's x^2, you know there will be two terms, and since it's -10, you know that one will be + and one will be -.

So (x - _) * (x + _)

Since it's 10, we know the last two digits have to multiply to 10. So it's either 1 and 10 or 2 and 5. Since we'll add two terms together to get +3, the only possible combination is +5 and -2.

So, (x - 2) * (x + 5).

Answer 6

with a single x^2 you're looking for a number that adds up to 3 and multiplies out to -10. Obviously one of the numbers (and only one) has to be negative. Look at it this way: (x+?)(x - ?).

Someone else will probably give you the answers, but I think you will gain more by understanding what you're doing.

Answer 7

(x + 5).(x - 2)

Answer 8

x^2 + 3x -10

x^2 - 2x +5x -10

x(x-2) + 5(x-2)

(x-2)(x+5)