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2 answers

first, 1 mph = 0.44704 m/s

so 40 mph = 17.9 m/s
I will use the 18 m/s you provided

using
v(t)=v0+a*t
18=a*5
a=3.6 m/s

Under constant acceleration the force in the horizontal direction (reaction of the road to the tires)
3600 N

There is also a vertical reaction force due to the weight of the car
1000*9.81
9810 N

The resultant vector is
sqrt(9810^2+3600^2)
=10450 N

j

2007-05-01 06:09:36 · answer #1 · answered by odu83 7 · 0 1

Since you did not state the frictional coefficient, I will assume it is a frictionless road. Therefore, using a free body diagram, the only force acting against the road is weight.


m*g = 1000*9.81 = 9810 N

2007-05-01 13:09:51 · answer #2 · answered by Anonymous · 0 1

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