Ty Pennington.hot or not?
2007-05-01 06:03:35 · 15 answers · asked by Norge 2 in Entertainment & Music ➔ Television
Hot Hot Hot
2007-05-01 06:06:09 · answer #1 · answered by ♥♥The Queen Has Spoken♥♥ 7 · 0⤊ 0⤋
The 3p^5 row of the periodic below nitrogen. Alkali metals and earth metals fill the next S orbital with 1 and 2 electrons respectively, while boron through neon begin to fill the P orbitals. The transition metals only fill s and d orbitals. I think pretty much always the s fills before the d orbitals even though it's in a higher energy shell because it's actually lower in energy. So c) is clearly not it. If you notice manganese is 5 blocks over in the transition metals. This means it has 5 d electrons. Copper is a notable exception and with a config of [Ar] 3d^10 4s^1. It actually fills the higher energy d orbital and has 10 d electrons instead of the predicted 9 from counting. So anyway, a) cannot be correct because you would fill the 3d^5 first instead of 4d^5. b) definitely cannot be it because it 7 d electrons AND it didn't fill the 4s orbital first. Hope this helps and gl with chem
2016-05-18 00:48:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Hot
2007-05-05 06:01:01 · answer #3 · answered by Anonymous · 2⤊ 0⤋
Definately HOT!!!!
Carter Osterhouse from Trading Spaces is better!
Check him out!!
2007-05-01 06:14:20 · answer #4 · answered by GASDIVA 5 · 1⤊ 1⤋
Funny and hot-though he has aged since his days on Trading Spaces. TOTALLY hot on T.S!!!
2007-05-01 07:20:42 · answer #5 · answered by ? 1 · 2⤊ 0⤋
hot
2007-05-01 08:01:06 · answer #6 · answered by michelle55552003 4 · 2⤊ 0⤋
Hot...I think it's his personality.
2007-05-01 06:10:30 · answer #7 · answered by Mom of 4 5 · 2⤊ 0⤋
I'm not sure!
lol
Sometimes I think he is but others he just seems so loud and annoying!
2007-05-01 07:44:23 · answer #8 · answered by AmyV 6 · 0⤊ 1⤋
funny not hot
2007-05-01 06:36:25 · answer #9 · answered by free2rhyme 4 · 0⤊ 1⤋
had to google him - hes kinda cute - but still dont know who the hell he is
2007-05-01 06:19:02 · answer #10 · answered by olivier1uk 3 · 0⤊ 1⤋