(x+2)² = -16x
x² + 4x + 4 = -16x
x² + 20x + 4 = 0
Use the quadratic formula x = {-b ± √(b² - 4ac) } / 2a
(here a=1, b=20, c=4)
x = {-20 ± √(20² - 4·4) } / 2
x = {-20 ± √384 } / 2
x = {-20 ± √(64·6) } / 2
x = {-20 ± 8·√6 } / 2
x = -10 + 4·√6 (= -0.2 approx)
and
x = -10 - 4·√6 (= -19.8 approx)
Hope this helps.
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2007-05-01 04:13:03
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answer #1
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answered by M 6
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x^2 + 4x + 4 + 16x = 0
x^2 + 20x + 100 - 100 + 4 = 0
(x + 10)^2 - 96 = 0
(x + 10 + 4sqrt6)(x + 10 - 4sqrt6) = 0
x = -10 - 4sqrt6
x = -10 + 4sqrt6
2007-05-01 04:39:12
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answer #2
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answered by Anonymous
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X^2+4X+4=-16
X^2+20x+4=0
solving this equation we'll have two answers for X:
X= -.2
X=-19.8
and both are rounded.
2007-05-01 04:17:34
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answer #3
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answered by Kiamehr 3
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(x+2)^2 = -16x
x^2 + 4x + 4 = -16x
x^2 + 20x + 4 = 0
x = (-20 +- root(20^2 - 4 * 4))/2
x = -10 +- 1/2 root (400 - 16)
x = -10 +- 1/2 root (384)
x = -10 +- 4root(6)
2007-05-01 04:15:58
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answer #4
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answered by Tim M 4
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x² + 4x + 4 = - 16x
x² + 20x + 4 = 0
x = [- 20 ± â(400 - 16) ] / 2
x = [- 20 ± â 384 ] / 2
x = [- 20 ± 19.6 ] / 2
x = - 0.2 , x = - 19.8
2007-05-01 04:47:21
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answer #5
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answered by Como 7
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