What is the average power consumption in watts of an appliance that uses 0.75kwh of energy in 1day?
with computations pls
2007-05-01 03:24:12 · 6 answers · asked by szhieru 1 in Science & Mathematics ➔ Physics
0.75 kwh=0.75 kilowatt-hours
(0.75 kilowatt-hours)*(1000 watts/kilowatt)=750 watt-hours
(750 watt-hours/day)/(24 hours/day)=31.25 watts
2007-05-01 03:31:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Average Power consumption per day = 0.75 x 24
= 18 kw
2007-05-01 10:30:01 · answer #2 · answered by becheras86 1 · 0⤊ 0⤋
Power is energy per time
P=E/t (Watt =(1 Joule)/(1 sec ) )
Watt-hours is energy consumed per 1 hour
1h= 3600 sec
1 day = 24 hour then we have
E=(0.75 E3 w/3600 )24 h= 5 Joules
P=E/sec=5/1sec= 5 watts
2007-05-01 10:28:27 · answer #3 · answered by Edward 7 · 0⤊ 0⤋
Average power P is ratio of work done W to time spent t
P=W/t
W=0.75 kWh=0.75*1000watt* 1 hour
=750 watt*3600 second
=2700000 watt second...............(1watt second=1joule)
Time t = 1 day=24 hour=24*60*60=86400 second
Average Power P=W/t =2700000 /86400 = 31.25 watt
Average Power = 31.25 watt
2007-05-01 10:49:40 · answer #4 · answered by ukmudgal 6 · 0⤊ 0⤋
Why does everyone make it so hard.
Total energy used = 0.75 kWh in 24 hours
So average power = 0.75/24 = 0.03125 kW
Or 31.25 W
2007-05-01 10:56:42 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Not sure...
2007-05-01 10:26:45 · answer #6 · answered by Sun Tan 2 · 0⤊ 1⤋