If you have two similar triangles one is :legs 6m, & 5m, base 3m, and the other triangle is legs 8m, the other leg has no measurement and the base is x. What is the measurement of x.
2007-05-01 00:50:01 · 3 answers · asked by Debra C 1 in Science & Mathematics ➔ Mathematics
6/8 = 3/x
6x = 3(8)
6x = 24
6x / 6 = 24 / 6
x = 24/6
x = 4
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2007-05-01 01:51:02 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Since they are similar triangles, then the lengths of each corresponding sides are proportional.
1. Identify the corresponding sides.
Note that the base 3m corresponds to the x which is the length of the base of the second triangle. Also, 6m corresponds to 8m on the second triangle.
2. Form the proportion equation.
3m/x = 6m/8m
3. Solve the equation. We do the cross product.
3m/x = 6m/8m
3m*8m = 6m*x
Then we divide both sides by 6m.
3m*8m/6m = 6m*x/6m. The 6m on the numerator and denominator will cancel out, so
(24/6)m = x
x = 4m.
:)
2007-05-01 00:59:25 · answer #2 · answered by wala_lang 2 · 0⤊ 0⤋
If the leg that is given is the corresponding leg of the first leg described, 6, then the base is a ratio of 6 to 8, or 4/3. So in this case, the base would be 4.
2007-05-01 00:55:30 · answer #3 · answered by badaerozepstones 3 · 0⤊ 0⤋