How is the formula constant velocity=(u+v)/2 derived?

Answer 1

It is not constant velocity but average velocity.
If the acceleration is constant, then the average velocity is the average of the maximum and the minimum velocity.

Hence,
v(av) = (u + v)/2

Hope this helps.

Answer 2

think of in case you cost a capacitor with a persevering with contemporary. The ability going into the capacitor at any on the spot of time is V*I, and the completed ability is the essential of that product. in spite of the undeniable fact that, V isn't consistent and will advance linearly with time (consistent contemporary). the completed ability inputted is then the time-honored voltage circumstances the present. If the capacitor is charged to a voltage V, the time-honored is V/2. it incredibly is the place the a million/2 comes from. Mathematically: E(t) = V*I; I = C*dV/dt; E(t) = C*V*dV/dt; E(t)*dt = C*V*dV combine the two factors to get ?E(t) that's the completed ability interior the capacitor E(finished) = C*?V*dV E(finished) = C*V²/2

Answer 3

Average velocity. Just like any other average formula.

Answer 4

u = ending velocity
v = beginning velocity
in the velocity doesn't change then all you have to do is even the difference of the two, hence divide the difference by 2.