u have to multiply it here.. (x^3)^2 = x^6
but (x^3)*(x^2) = x^5
2007-04-30 20:51:56
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answer #1
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answered by Anonymous
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Instead of trying to memorize a rule, just work it out:
(x^3)^2 = (x^3)(x^3) = (x*x*x)(x*x*x) = x*x*x*x*x*x = x^6
Unduly pedantic, but it is obvious that you multiply the exponents. As seen in the second step, you add when multiplying the same variable raised to whatever powers with a simple degenerate case of:
(x^1)(x^1) = x^2
Of course, this is hardly a proof, but easy to confirm without resorting to an authoritative reference.
2007-04-30 21:17:56
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answer #2
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answered by Anonymous
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multiply the powers.
x^(3*2)
=x^6
2007-04-30 20:51:56
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answer #3
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answered by iyiogrenci 6
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(X^3)^2 = X^3 x X^3 = X^6
So you multiply it
You only add it if you multiply it with another X^anything
2007-04-30 20:52:07
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answer #4
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answered by Anonymous
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x^6
2007-04-30 20:56:43
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answer #5
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answered by Rohini S 1
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multiply them: x^6
the addition is for this case:
x^2*x^3 = x^(2+3) = x^5
2007-04-30 20:52:40
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answer #6
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answered by Anonymous
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x^6
When it is (x^3)^2 you multiply --> x^6
When it is x^3 * x^2 then you add --> x^5
2007-04-30 20:51:04
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answer #7
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answered by ........ 5
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x³ X x³ = x^(6)
Rule is to add indices when multiplying.
2007-04-30 20:53:15
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answer #8
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answered by Como 7
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(x^3)^2=x^3).x^3)=X^(3+3)=X^6
2007-04-30 20:52:38
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answer #9
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answered by Ahmad k 2
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what year are you in? I'm in my second last year of senior high school and I learnt it four years ago. anyway i checked and it should be x^6
2007-04-30 21:06:32
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answer #10
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answered by Anonymous
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