What will be the new volume if 125 mL of He gas at 100°C and 0.983 atm is cooled to 24°C and the pressure is increased to 1.05 atm?
my answer is 52.2 mL
2007-04-30 20:06:21 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
I got 93.2 ml
I used Pi*Vi/ Ti= Pf*Vf*/ Tf
plug in:
Pi =.983 atm
Vi = .125 L
Ti = 373 Kelvins (you have to convert = 100+273)
Pf = 1.05 atm
Tf = 297 Kelvins (24+273)
Then you can solve for Vf
2007-04-30 20:10:25 · answer #1 · answered by Sam 5 · 0⤊ 0⤋
T = 100 + 273 = 373 K
V = 125 mL =.0.125 L
n = pV / RT = 0.983 x 0.125 / 0.0821 x 373 =0.00402 mole He
T = 24 + 273 =297 K
V = nRT / p = 0.00402 x 0.0821 x 297 / 1.05 = 0.0933 L
2007-04-30 20:15:56 · answer #2 · answered by Non più attiva su answers 7 · 0⤊ 0⤋
your awnser should be 0.046594 litres or 46.59 ml
2007-04-30 20:28:16 · answer #3 · answered by Akshay I 1 · 0⤊ 1⤋
93.18 ml
Use PV/T = constant.
2007-04-30 20:17:33 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋