No, plugging in 5 gives you 25 - 50 = -25, not -10.
x² - 10x + 10 = 0
Using quadratic formula:
x = {10 ± √[100 - 40]} / 2
= 5 ± 1/2 √[60]
= 5 ± 1/2 √[(4)(15)]
x = 5 ± √[15]
2007-04-30 19:39:24
·
answer #1
·
answered by Chris H 4
·
0⤊
0⤋
NO.
x^2 - 10x = -10
x^2 - 10x + 10 = 0
Use General Formula for this part.
x= 8.87 or x =1.13
2007-05-01 02:37:59
·
answer #2
·
answered by Winter Angel 2
·
0⤊
0⤋
x² - 10x + 10 = 0
x = [10 ± â(100 - 40)] / 2
x = [10 ± â60] / 2
x = [10 ± 2â15] / 2
x = [ 5 ± â15]
2007-05-01 03:21:32
·
answer #3
·
answered by Como 7
·
0⤊
1⤋
nope
Must use the quadratic formula
a=1 b = -10 c = 10
discriminant b^2 - 4ac (the part under the square root in quadratic formula) is less than zero
(-10)^2 - 4(1)(+10) = 100 - 40 = 60
sqrt 60 = 2sqrt15
x = [ +10 +/- 2sqrt15 ] / 2
x= 5 +/- sqrt15
2007-05-01 02:36:48
·
answer #4
·
answered by Anonymous
·
0⤊
1⤋
x^2-10x+10=0
no solution
2007-05-01 02:36:42
·
answer #5
·
answered by NDN 5
·
0⤊
2⤋
No the ans is not 5.(since 5*5=25 & not 10)
u will have to use formula:
x = -b [+(or)-] [root (b^2-4ac)]/2a
in ur question, b= -10 , a = 1,c= 10;
2007-05-01 02:40:53
·
answer #6
·
answered by sweety 2
·
0⤊
1⤋
There is a solution...try completing the sqaures
2007-05-01 02:38:14
·
answer #7
·
answered by matthias c 2
·
0⤊
1⤋