x^2 - 26x + 48 = 0. How do you solve for X?

Answer 1

Factor and use zero property rule
Find two numbers that multiply to 48 and add to 26
1*48
2*24
3*16
4*12
6*8 . . .

it is 24 and 2

(x-24) (x-2) = 0

x=24 or x=2

Answer 2

There are a number of different ways. If you have a graphing calculator, I suggest plotting the equation and using the calculator to find the zeroes. Those are the solutions of x. If not, you'll need to use the quadratic formula, which is

x = [-b +/- sqrt(b^2 - 4ac)] / 2a

For your equation,
a = 1
b = -26
c = 48

x = [26 +/- sqrt(26^2 - 4(1)(48))] / 2(1)
x = (26 +/- 22) / 2
x = 26 + 22 / 2
AND
x = 26 - 22 / 2
x = 2 and 24

You can also factor the equation:
(1) Find two factors of 48 that when combined, equal 26.

Those factors are 24 and 2

x^2 - 26x + 48 = 0
x^2 - 24x - 2x + 48 = 0
(x^2 - 24x) - (2x - 48) = 0
x(x - 24) - 2(x - 24) = 0
(x - 2)(x - 24) = 0

x - 2 = 0
x =2

x - 24 = 0
x = 24

The solutions are 2 and 24.

Answer 3

Factor and use zero property rule
Find two numbers that multiply to 48 and add to 26
1*48
2*24
3*16
4*12
6*8 . . .

it is 24 and 2

Now factorise them:


Use completing the square or factorization.
x^2 - 26x + 48 = 0
(x-24)(x-2) = 0
x=24 or x=2

therefore x-24 = 0 or x-2 = 0, so x = 2 or 24.

Answer 4

Use completing the square or factorization.
x^2 - 26x + 48 = 0
(x-24)(x-2) = 0
x=24 or x=2

Answer 5

You can use the quadratic formula, and can also factor this polynomial to get the zeros.
Factoring yields: x^2 - 26x +48 = (x - 24)(x - 2)

So, (x - 24)(x - 2) = 0 implies either x = 24, or x = 2. You can substitute either 24 or 2 into your equation and see that both are solutions.

Answer 6

This is a quadratic equation and the first thing you have to do is factor the equation.

x^2 - 26x + 48 = 0
(x - 24)(x - 2) = 0
x = 24, x = 2

Answer 7

Fill interior the criteria in line with what you be attentive to: The x^2 coefficient is one so fill in an x in each and each element: (x +- ??)(x +- ??) = 0 simply by fact the 40 8 is valuable, the two indications interior the criteria are a similar. simply by fact the x term has a damaging coefficient, the two indications could be minus indications: (x - ??)(x - ??) = 0 Now all you like are 2 factors of 40 8 which upload as much as 26. The numbers 2 and 24 meet the two standards: (x - 2)(x - 24) = 0 x = 2 and x = 24

Answer 8

Look for factors of 48 that add to 26: they are 24 and 2.
So we factorise as (x-24)(x-2) = 0
and therefore x-24 = 0 or x-2 = 0, so x = 2 or 24.

Answer 9

x -------- 24
x -------- 2 ( factorise )
___________
x^ 2 ------ 48


( x - 24 ) ( x - 2 ) = x^2 - 26x + 48

x - 24 = 0 x - 2 = 0
x = 24 or x = 2

Sorry, i don't know how to explain.

Answer 10

(x-24)(x-2)=0 implies x=24 or 2