A rectangle has a width of 5sqrt2 cm and a length of 10sqrt2 cm. Since area is length times width, what is the area of this rectangle?
2007-04-30 19:30:43 · 5 answers · asked by sonne_engel 1 in Science & Mathematics ➔ Mathematics
A = W * L
A = (5 * sqrt(2)) * (10 * sqrt(2))
Using commutative and associative properties of multiplication:
A = (5*10) * (sqrt(2) * sqrt(2))
A = 50 * (sqrt(2))^2
A = 50 * 2 = 100 sq. cm
2007-04-30 19:44:39 · answer #1 · answered by theoryofgame 7 · 1⤊ 0⤋
A = L x B
A = 10 â2 x 5 â2
A = 50 x 2 (note that â2 x â2 = 2)
A = 100 cm²
2007-05-01 03:29:31 · answer #2 · answered by Como 7 · 0⤊ 0⤋
5sqrt 2 X 10sqrt 2 = 5X 10 Xsqrt2 X sqrt2
becos when sqrt 2 X sqrt 2 = 2
so 5 X 10 X2 =100
2007-05-01 02:41:27 · answer #3 · answered by Jenny 2 · 1⤊ 0⤋
you can combine roots. sqrt2 * sqrt2 = sqrt4 = 2 so you have 2 x 5 x 10 = 100 squared centimeters
2007-05-01 02:37:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋
50sqrt2 cm
2007-05-01 02:40:41 · answer #5 · answered by i_dont_know 2 · 0⤊ 1⤋