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If 6.00 L of an ideal gas is cooled from 51°C to -272°C, what will the volume of the gas become?

my answer is 0.0185 L

2007-04-30 19:24:07 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Yes, that's correct; it's being cooled from 324K to 1K, so the volume is multiplied by 1/324.

2007-04-30 19:27:52 · answer #1 · answered by Scarlet Manuka 7 · 0 0

using ideal gas eqn: v1/t1=v2/t2, (where v1 is the initial volume, t1 is the initial temperature) you will get the value of v2
as 6/324 which is 0.01851852. which means u are right....

2007-05-01 02:52:40 · answer #2 · answered by Akshay I 1 · 0 0

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