do side lengths of 9,12 and 5 units form right triangle
2007-04-30 19:16:08 · 6 answers · asked by butterfly 1 in Science & Mathematics ➔ Mathematics
no these are not the sides of a right triangle because according to the rule of a right angle triangle the square of the longest side is equal to the sum of squares of the other two sides
here 12*12 is not equal to 9*9+5*5
144 is not equal to 81+25 i.e 106
2007-04-30 19:24:14 · answer #1 · answered by rajesh 2 · 0⤊ 0⤋
In a right triangle, the sum of the squares of the shorter sides equal the square of the longest (Pythagorean Theorem):
a^2 + b^2 = c^2
Lets check your sides:
5^2 + 9^2 = 12^2 ?
25 + 81 = 144 ?
106 = 144 ?
The equation is not true, so the triangle the side lengths you game do not form a right triangle.
2007-05-01 02:20:54 · answer #2 · answered by theoryofgame 7 · 0⤊ 0⤋
No they dont: let 12 be the hypotenuse (longest side of the triangle)
9^2 + 5^2 = 106
106 square root not equals to 12.
Therefore they dont form a right-angled triangle
2007-05-01 02:19:12 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a^2+b^2=C^2
12 is C which is the Hypotenuse, because Hypotenuse is the longest side.
9 and 5 are the legs.
5^2+9^2=12^2
25+81=144
106=144
No they do not form a right triangle.
2007-05-01 02:26:08 · answer #4 · answered by Sir Oxide 3 · 0⤊ 0⤋
no
since 12^2 = 144 9^2=81 5^2= 25
81+25= 106
and to have a right triangle , you should find 144 accoding to Pythagorus theorem
2007-05-01 02:24:21 · answer #5 · answered by maussy 7 · 0⤊ 0⤋
No, but 9, 12, and 15 do.
2007-05-01 02:19:44 · answer #6 · answered by duggles 2 · 0⤊ 0⤋