Runners on 1st and 2nd. The pitcher throws to first to try and pick off the runner but throws wildly into the stands. How far do the runners advance?
2007-04-30 19:15:26 · 12 answers · asked by Nitz Frugent 6 in Sports ➔ Baseball
Simple play -- if the pitcher steps off the rubber with his pivot foot (same foot as his glove is on) before step it is a two base award as he is now considered an infielder for throwing purposes.
If he simply steps or "Jump turns" to first then it is a one base award as he is still considered in contact with the rubber. (Same concept as with a wild pitch that goes out of play.)
2007-05-01 01:09:52 · answer #1 · answered by david w 6 · 1⤊ 0⤋
Two bases.
MLB Rule 7.05:
Each runner including the batter-runner may, without liability to be put out, advance --
(g) Two bases when, with no spectators on the playing field, a thrown ball goes into the stands, or into a bench (whether or not the ball rebounds into the field), or over or under or through a field fence, or on a slanting part of the screen above the backstop, or remains in the meshes of a wire screen protecting spectators. The ball is dead. When such wild throw is the first play by an infielder, the umpire, in awarding such bases, shall be governed by the position of the runners at the time the ball was pitched; in all other cases the umpire shall be governed by the position of the runners at the time the wild throw was made;
2007-04-30 20:19:49 · answer #2 · answered by Chipmaker Authentic 7 · 1⤊ 1⤋
The runners can advance as many bases as they can as long as the ball is in play. If the ball lands in the stands or dugout or somewhere that is consider out of play the runners will get only one base.
2007-05-01 00:01:24 · answer #3 · answered by dwade3 3 · 0⤊ 0⤋
If the pitcher was still on the rubber when he threw to first, the runners would be awarded one base: the runner on second would advance to third and the runner on first would advance to second.
If the pitcher had stepped off before throwing, the runners would be awarded two bases: the runner on second would be awarded home and the runner on first would be awarded third.
2007-04-30 20:43:04 · answer #4 · answered by Ryan R 6 · 1⤊ 0⤋
Both runners advance two bases when a ball is thrown out of play. The runner at second base advances to home; the runner at first base advances to third base. Had the ball remained in play (retrievable by a fielder), both runners could have advanced at their own risk.
2007-04-30 19:37:44 · answer #5 · answered by Anonymous · 0⤊ 1⤋
The runners can advance as many bases as they can as long as the ball is in play. If the ball lands in the stands or dugout or somewhere that is consider out of play the runners will get only one base.
2007-04-30 19:21:35 · answer #6 · answered by MD67 1 · 1⤊ 1⤋
Joe M has it right, two bases. Runners are awarded two bases for a ball that goes out of play.
2007-04-30 20:17:25 · answer #7 · answered by dodger5588 3 · 0⤊ 1⤋
If the ball goes out of play (i.e., into the dugout or the stands) they can only advance one base if his foot was on the rubber. Otherwise, two bases.
2007-05-01 05:26:03 · answer #8 · answered by cubspatssox 2 · 0⤊ 0⤋
No, this is in no way been completed. the closest became bill Mazeroski's homerun maximum advantageous off the 9th inning which ended the sequence, giving the Pirates the championship. it continues to be the only game 7 walk-off homestead run in international sequence historic previous.
2017-01-09 05:24:56 · answer #9 · answered by sak 4 · 0⤊ 0⤋
1 base. that's the rule from little league to the majors.
2007-04-30 20:12:31 · answer #10 · answered by shayne t 2 · 0⤊ 1⤋