Suppose you wanted to produce 1 Liter of a 3.5 Molarity solution of H2SO4.
1) What is the solute?
2) What is the solvent?
3) How many grams of solute are needed to make this solution?
4) How many grams of solute are needed to make 2.5 L of a 1.75 M solution of Ba(NO3)2
2007-04-30 17:39:37 · 1 answers · asked by carmen 2 in Science & Mathematics ➔ Chemistry
Whatever you do, don't try to do this. Sulfuric acid (the solute) and water (the solvent) must be handled very carefully. The number of moles = Volume x molarity. For your 3.5M solution, you need 3.5 moles of sulfuric acid. Just figure the mol wt of H2SO4 (about 98), and multiply by 3.5.
Problem 4 uses the same formula to find moles of Barium nitrate. Again, you will have to find the mol wt of barium nitrate to find the grams.
2007-04-30 17:48:07 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋