how do you do this math problem?

Question

2p-5q=11
2p+5q=1
Use substitution, addition/subtraction, or linear combinations to solve the linear system. Tell which method you chose. Check the solution in each in each of the original equations.

thanx

Answer 1

2p-5q=11
(+) 2p+5q=1
__________

4p=12 p=12/4=3
__________
substituting in any of the equation let us substitute in 2p-5q=11
2*3-5q=11
6-5q=11
-5q=11-6
-5q =5
q=5/-5= -1

Answer 2

2p-5q=11
2p+5q=1
Use addition/subtraction

4p = 12
p=3
q=-1

2·3 - 5·-1 = 11
6 + 5 = 11

and

2·3 + 5·-1 = 1
6 - 5 = 1

Answer 3

2p-5q=11
2p+5q=1 add
4p=12 divide both sides by 4
p=3
2p+5q=1 substitute 3 for p
2*3+5q=1
6+5q=1 subtract 6 from each side
5q=-5 divide both sides by 5
q=-1

(4, -1)

check
2*3-5(-1)=11
6+5=11
11=11

2*3+5(-1)=1
6-5=1
1=1

Answer 4

Since you have a -5q and 5q in the equations, addition looks good. Then we have 4p=12 and p=3. Back substiuting into the 2d eqtn, we have 6+5q=1 or q= -1

Answer 5

You can just subtract them.

2p-5q=11
2p+5q=1

2p-2p = 0
-5q- 5q = -10q
11 - 1 = 10

-10q = 10
q = -1

To get P, plug in -1 for q,

2p-5(-1)=11
2p+5=11
2p=6
p=3

Answer 6

I love these! OK, add the second equation to the first:

2p-5q=11
2p+5q=1
_______
4p = 12
p=3

then substitute into either equation for q, finding that q= -1

Answer 7

2p-5q=11 hence 2p=11+5q p=11/2 +5/2 q

2(11/2+5/2q)+5q=1

11+5q+5q=1 hence 10q=1-11 hence 10q=-10

q=-10/10=-1

2p-5q=11 hence 2p+5 =11 hence 2p=11-5=6

p=6/2=3

Answer 8

you need to solve one of the equations for one of the variables. solving the first equation for p, you get p=(11+5q)/2. plug that value of p into your second equation. So when you do that there is only one variable in the second equation, which is q. When you solve this for q, your get q=-1. Plug -1 in for q in any of these equations and you will find that p=3.

Answer 9

add these eq
then 4p=12
then p=3;
put ineq 1
then q=-1