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How many real roots exist if the discriminant of the equation = 0?
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2007-04-30 16:40:10 · 3 answers · asked by kenane w 1 in Science & Mathematics Mathematics

3 answers

1 distinct root

2007-04-30 16:43:13 · answer #1 · answered by bruinfan 7 · 0 0

As James K said, there is one distinct real root when the discriminant is 0. (And 2 when it is positive, and none when it is negative.)

Note that he said DISTINCT real root. Sometimes the root in this situation is referred to as a double root, so that we can say that the quadratic equation has two roots, as it is supposed to. (They just happen to be equal in this case.)

2007-04-30 16:52:44 · answer #2 · answered by actuator 5 · 0 0

D= 64 - 4.16= 0 the only one soluition because x1,2 = - b ± D^1/2

2016-05-17 21:52:25 · answer #3 · answered by aaron 3 · 0 0

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