With 50/50 chance of winning, what is the probability of losing 5 consecutive times?

Question

Pls. provide solution if possible. Thanks!

Answer 1

1/32

To get this note that the probability of loosing each game is 1/2, so the probability of 5 in a row is (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = (1/2)^5 = 1/32 or about a 3% chance.

Answer 2

5 different trials, the chances of losing is 1/2.

prob. of losing 5 straight times = 1/2 * 1/2 * 1/2 * 1/2 * 1/2

=(1/2)^5 = (1/32)

there is a 1 in 32 chance of losing 5 straight times

Answer 3

if you have 50/50 chance of winning then it means that you are going to win 1/2 (0.5) of the time and lose 1/2 (0.5) of the time..

my solution is to just muliplty 1/2 (0.5) by 5 times
so 0.5x0.5x0.5x0.5x0.5
the answer is

0.03125..

Answer 4

To lose 5 consecutive times would have to lose EACH time.
ie lose 1st time
and
lose 2nd time
and
lose 3rd time
and
lose 4th time
and
lose 5th time
P(lose 5 consecutive times ) = (1/2)^5 = 1/32

Answer 5

1/2 x 1/2 x 1/2 x 1/2 x 1/2 = Y

you have to do the rest on your own

Answer 6

the possibilities of them prevailing are solid, they owned england contained in the ashes 5-0 so i say they have a 25% probability of prevailing the different 75% is both pakistan , india, or south africa South Africa beat Pakistan in attempt series( im a pakistani through ways) India beat West Indies contained in the odi's 3-a million and Pakistan beat West Indies contained in the three attempt series

Answer 7

(1/2)^5=1/32

Answer 8

3.125%. Where;

1) 50%
2) 25%
3) 12.5%
4) 6.25%
5) 3.125%

Answer 9

i think it is 0 because if u have like 100% of winning how would u lose???