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csc theta (1 - cos^2 theta)

2007-04-30 15:39:59 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

csc θ = 1/sin θ.
1- cos²θ = sin²θ.
So the whole expression is sin² θ/ sin θ = sin θ.

2007-04-30 16:09:01 · answer #1 · answered by steiner1745 7 · 0 0

csc(theta) * sin^2(theta).......1-cos^2(theta) = sin^2(theta)

1/sin(theta) *sin^2(theta).....csc = 1/sin

sin(theta)

2007-04-30 15:45:25 · answer #2 · answered by Mary E 3 · 0 0

First one: in view that csc? = a million/sin?, the question turns into =(a million/sin?)(sin?) - sin^2? =a million - sin^2? Now, utilising the reality that sin^2? + cos^2? = a million you could locate that it turns into =cos^2? 2nd one: a million/sin? - a million/cos? ----------------------- cos?/sin? - sin?/cos? you could desire to combine the fractions by utilising getting straightforward denominators: cos?/sin?cos? - sin?/sin?cos? --------------------------------------... cos^2?/sin?cos? - sin^2?/sin?cos? Now, in view that they have straightforward denominators, subtract: (cos?-sin?)/sin?cos? ------------------------------ (cos^2?-sin^2?)/sin?cos? To divide fractions, multiply be the reciprocal: (Please forget approximately bearing directly to the .....) (cos? - sin?).........(sin?cos?) ------------------ x ---------------------- (sin?cos?)..........(cos^2? - sin^2?) Cancel the sin?cos?'s leaving cos? - sin? --------------- cos^2? - sin^2? ingredient the backside as a distinction of squares cos? - sin? -------------------------- (cos?-sin?)(cos?+sin?) Cancel the cos?-sin? a million -------------------- cos?+sin?

2016-12-16 20:02:27 · answer #3 · answered by Anonymous · 0 0

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