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2007-04-30 15:34:45 · 4 answers · asked by (^_^) CHiccaaqui(^_^) 4 in Science & Mathematics Chemistry

I know the answer to the question, but I need an explanation. Help!

2007-04-30 15:39:16 · update #1

4 answers

"Air" has an effective mole weight of 29
Water has an effective mole weight of 18.
In an ideal gas comparison, the component with the higher mole weight has the higher density.

2007-04-30 15:44:19 · answer #1 · answered by cattbarf 7 · 1 1

The "effective mole weight" is pretty much meaningless. The gas we call "air" is present in the same amount in a given amount of "air" regardless of the moisture content. So the important factor is not the air itself, but the fact that the higher the moisture level, the more material in the given amount of what-have-you. So the higher the moisture, the more stuff in the chosen volume which is pretty much a definition of "denser." It is, for instance, the reason steel is denser than water, but if you make a large air filled space with a small amount of steel it can float (if formed appropriately) because less material in a given volume is "less dense."

2007-04-30 15:58:38 · answer #2 · answered by roynburton 5 · 0 0

reachable :) Humid air with the aid of actuality that it contains water vapor! Water as everybody is familiar with is larger dense than air (with the aid of actuality we are able to shelter it in swimming swimming pools =P) and so, including the full water ingredient to the air clearly makes it extra dense than air with none aspects.

2016-12-16 20:02:21 · answer #3 · answered by Anonymous · 0 0

Dry air = no water
Moist air = dry air + water

So the latter must be denser because it has more stuff in it.

2007-04-30 15:37:54 · answer #4 · answered by ZeroCarbonImpact 3 · 1 1

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