The coefficient of static friction on an unbanked roadway is 0.4. The roadway has a radius of curvature of 100

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The coefficient of static friction on an unbanked roadway is 0.4. The roadway has a radius of curvature of 100

100 m. The maximum speed at which a 2000 kg car can safely negotiate this roadway is

2007-04-30 15:33:15 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics

1 answers

...And the roadway is not banked, right? Then it will take 0.4g of lateral (centripetal) acceleration to slide out. Centripetal acceleration = v^2/r = 0.4g, so v=sqrt(0.4gr). This is independent of the car's mass.

2007-05-01 05:51:46 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋