A sample of gas at 0.830 atm and 25.0 celcius has a volume of 2.00L. What will its volume be at STP?
2007-04-30 14:43:23 · 5 answers · asked by pirateprincess 2 in Science & Mathematics ➔ Chemistry
Combined Gas Law
Pressure(1)=0.830atm
Temperature(1)=25.0C +273K=298K
Volume(1)=2.00L
Pressure(2)=1.00atm
Temperature(2)=273K
Volume(2)=?
P1V1/T1=P2V2/T2
V2=(P1V1T2)/P2T1
V2=(0.830atmx2.00Lx273K)/1.00atmx298K
V2=1.52L
2007-04-30 14:46:07 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Use combined gas law:
(V1 * P1 / T1) = (V2 * P2 / T2)
STP means standard temperature and pressure (1 atm and O C)
From info given:
V1 = 2.00 L
P1 = 0.830 atm
T1 = 25.0 C = 298 K (add 273 to convert C to K)
V2 = ?
P2 = 1.00 atm
T2 = 0 C = 273 K
Solve for V2 by cross multiplying:
V2 = (P1 * V1 * T2) / (P2 * T1)
Just plug in your numbers.
2007-04-30 21:51:13 · answer #2 · answered by Mark M 2 · 0⤊ 0⤋
Use the ideal gas law eqtn:
pV=nRT
0.83x 2 = nR (298)
use it again
1 x V = nR (273)
Make a proportion
V/1.66 = 273/298 and solve for V in Liters.
2007-04-30 21:49:20 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
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2007-04-30 21:54:31 · answer #4 · answered by <-·´¯`·. [dannyel] .·´¯`·-> 3 · 0⤊ 0⤋
P1V1=P2V2
(0.83 atm)(2.00 L) = (1 atm)V2
V2 = [(0.83 atm)(2.00 L)] / 1 atm
V2 = 1.66 L
2007-04-30 21:51:07 · answer #5 · answered by Yssa A 3 · 0⤊ 1⤋