prime factors of #s please?

Question

142 [[[[[ anyone please}}}}}}}}}}}}}
45
56
63
236
12
110
46
84

Answer 1

142 / 2 = 71, which is prime. So its prime factors are 2 and 71.

45 = 9 * 5 = 3 * 3 * 5
56 = 7 * 8 = 7 * 2 * 2 * 2
63 = 7 * 9 = 7 * 3 * 3

236 = 118 * 2 = 59 * 2 * 2 (59 is prime)

12 = 4 * 3 = 2 * 2 * 3
110 = 11 * 10 = 11 * 5 * 2
46 = 23 * 2 (23 is prime)
84 = 4 * 21 = 2 * 2 * 3 * 7

It's pretty easy to factor the numbers. Just find a number that divides into it, and split it up, and then look for prime factors in each of the smaller numbers (e.g., 84 -> 4 * 21, and 4 -> 2 * 2 and 21 -> 3 * 7)

Answer 2

142 = 2 . 71
45 = 3^2 . 5
56 = 2^3 . 7
63 = 3^2 . 7
236 = 2^2 . 59
12 = 2^2 . 3
110 = 2 . 5 . 11
46 = 2 . 23
84 = 2^2 . 3 . 7

Answer 3

go to wikipedia.com and there's this really good pg. which has it all up to 1,000! i used it a few months ago when we had to do allll the prime factor stuff :/

here's the site:
http://en.wikipedia.org/wiki/Table_of_prime_factors

hope i helped sweetie <3