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A .400 kg green bead slides on a curved frictionless wire, starting from rest at point A. At point b the bead collides elastically with a .600 kg blue ball at rest. Find the maximum height the blue ball rises as it moves up the wire.
Point A is 1.50 m above the ground while point b is on the ground. So the bead from point A slides down the wire to point b.

2007-04-30 13:09:09 · 3 answers · asked by rageamos 1 in Science & Mathematics Physics

3 answers

Just prior to the collision, the bead has KE equal to the lost PE, i.e. KE = 1/2 mv^2 = mgh => v^2 = 2gh = 2(9.81)(1.50) = 29.43, so v = 5.425 m/s.
Conservation of momentum:
m1u1 + m2u2 = m1v1 + m2v2
=> 0.400(5.425) + 0 = 0.400 v1 + 0.600 v2
=> v1 = 5.425 - 1.50 v2.
Elastic collision:
m1u1^2 + m2u2^2 = m1v1^2 + m2v2^2
=> 0.400(5.425)^2 + 0 = 0.400 v1^2 + 0.600 v2^2
Substitute in our expression for v1:
0.400 (5.425)^2 = 0.400 (5.425 - 1.50 v2)^2 + 0.600 v2^2
=> 1.500 v2^2 - 6.510 v2 = 0
=> v2 = 0 or v2 = 6.510 / 1.500
(v2 = 0 is the state before the collision, we want the state after the collision)
So v2 = 4.340 m/s and the ball has kinetic energy 1/2 (0.600) (4.340)^2 = 5.651 J.
This will be transformed into PE, so we have
5.651 = mgh = 0.600(9.81) h => h = 0.960 m.

2007-04-30 13:21:33 · answer #1 · answered by Scarlet Manuka 7 · 0 1

The potential energy of the green bead started out as 600 kg-m, because it was a 400 kg bead 1.5 m above the ground state (we can ignore the fact that energy is normally measured in newton-meters because the same conversion factors would be applied to both sides of the equation). The green bead accelerates and gains energy until it impacts the blue bead. It imparts all of its energy and momentum to the blue bead. The 600 kg blue bead rises until all of its kinetic energy is converted to 600 kg-m of potential energy. Since its mass is 600 kg, its height above the ground state must be 1 m for the product of height and mass to be 600 kg-m. So, it rises to 1 meter.

2007-04-30 13:22:42 · answer #2 · answered by PoppaJ 5 · 0 1

If the two autos are traveling opposite guidelines and that they collide head on? conservation of linear momentum. if the velocities are a similar, then the autos will commute interior the process the better motor vehicle after the collision, yet at a slower velocity. The collision would be inelastic. climate or no longer it somewhat is thoroughly inelastic relies upon. At a extra suitable velocity the autos will possibly mesh at the same time interior the supply way steel and bring about a wonderfully inelastic collision.

2016-12-16 19:53:22 · answer #3 · answered by ? 4 · 0 0

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