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F(x)=7x^2/5-9x^4/5

Use C to denote an arbitrary constant

2007-04-30 12:35:26 · 2 answers · asked by sunyrob 1 in Science & Mathematics Mathematics

2 answers

f(x) = 7x^2/5 - 9x^4/5

∫(7x^2/5 - 9x^4/5)dx
= 7(5/7x^7/5) - 9(5/9x^9/5) + C
= 5x^7/5 - 5x^9/5 + C

2007-04-30 12:41:35 · answer #1 · answered by skm4usa 3 · 0 0

What you have here is of the form
ax^k1 - bx^k2
so the general form of the antiderivative is going to be
(a/(k1 + 1))X^(k1 +1) - (b/(k2 + 1))x^(k2 +1) + C.

HTH

Doug

2007-04-30 12:42:43 · answer #2 · answered by doug_donaghue 7 · 0 0

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