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Use Newton's method to find all the roots of the equation e^-x = 7+x correct to eight decimal places.

2007-04-30 12:32:49 · 1 answers · asked by sunyrob 1 in Science & Mathematics Mathematics

1 answers

e^-x = 7 + x
y = 7 + x - e^-x = 0
∆y/∆x = 1 + e^-x
∆y/(1 + e^-x) = ∆x
x = x + (e^-x - x - 7)/(1 + e^-x)
0
-3
-2.237129366
-1.79304731
-1.678776483
-1.672836611
-1.672821699
-1.672821699

2007-04-30 13:08:11 · answer #1 · answered by Helmut 7 · 0 0

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